 | Robert Stuart - 1854 - 1272 páginas
...hypothenuse AC, when the square of 189 AB has been subtracted. 189 Prob. 4. To find the area of a trapezoid. Multiply the sum of the two parallel sides by the...between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and the perpendicular distance AP or CN... | |
 | Thomas Tate - 1855 - 286 páginas
...Theorem. From this theorem we derive the following rule for finding the area of a trapezoid. ROLE. Multiply the sum of the two parallel sides by the...between them, and half the product will be the area of the trapezoid. Ex. 1. Required the area of a trapezoid A BCD, when AB = 6 ft, DC = 4 ft., and the... | |
 | Charles Guilford Burnham - 1857 - 342 páginas
...What is the area ? Ans. 24 chains. Art. 271 . — To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides by the perpendicular distance between them : the product will be ilie area. 1. What is the area of a piece of land that is 30 chains long, 20... | |
 | Charles Guilford Burnham - 1857 - 328 páginas
...What is the area ? Ans. 24 chains. Art. 271. — To find the area of a trapezoid. RULE. Multiply half the sum of the two parallel sides "by the perpendicular distance between them : the product will be the area. 1. What is the area of a piece of land that is 30 chains long, 20 chains... | |
 | Anthony Nesbit - 1859 - 494 páginas
...? Ans. 1131 ft. 2 in. 9 pa. PROBLEM To find the area of a trapezoid. RULE. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will give the area. EXAMPLES. 1 . What is... | |
 | Alfred Newsom Niblett - 1861 - 204 páginas
...NB—In this figure the dotted lino shows the perpendicular height. RULES. Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Or, half the sum of the sides multiplied by their distance will give the area. PEOBLEM 5. To find the... | |
 | Josiah Lyman - 1862 - 92 páginas
...area of the field. SECOND METHOD. (S9.) BY TRAPEZOIDS AND TRIANGLES. For a Trapezoid, the rule is, Multiply the sum of the two parallel sides by the perpendicular distance between them. Half the product will be the area. For a Triangle, Multiply the base by the perpendicular height, and... | |
 | Oliver Byrne - 1863 - 600 páginas
...a trapezoid, or a quadrangle, two of whose opposite sides are parallel. — Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. Required the area of the trapezoid ABCD, whose sides AB and DC are 321-51 and 214-24, and perpendicular... | |
 | William John Macquorn Rankine - 1866 - 356 páginas
...by a pair of parallel straight lines, and a pair of straight lines not parallel). Multiply the half sum of the two parallel sides by the perpendicular distance between them. 3. Triangle. RULE A. — Multiply the length of any one of the sides by one-half of its perpendicular... | |
 | Isaac Todhunter - 1869 - 312 páginas
...CE into half the sum of AB and CD. Thus we obtain the rule which will now be given. 161. To find the area of a trapezoid. RULE. Multiply the sum of the...between them, and half the product will be the area. 162. Examples : (1) The two parallel sides of a trapezoid are 2 feet 6 inches, and 3 feet 4 inches... | |
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Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. 
